论文标题

$ z \ to b \ bar b $前向不对称,cabibbo角异常,$τ\toμLνν$和$ b \ to s \ ell^+el^ - $ data的组合解释

Combined Explanation of the $Z\to b\bar b$ Forward-Backward Asymmetry, the Cabibbo Angle Anomaly, $τ\toμνν$ and $b\to s\ell^+\ell^-$ Data

论文作者

Crivellin, Andreas, Manzari, Claudio Andrea, Alguero, Marcel, Matias, Joaquim

论文摘要

在本文中,我们提出了一个简单的模型,可以将$ z \ to提供$ z \ b \ b $前向不对称的$ z \的组合说明,cabibbo角度异常(CAA),$τ\toμνν$和$ b \ to s \ ell^ell^+^+\ ell^ell^ell^ - $数据。该模型是通过将标准模型(SM)通过两个重型矢量的夸克($ su(2)_l $ doublet(Singlet)扩展的,具有$ -5/6 $ -5/6 $(-1/3)),两个新的标量(一个中性和一个单人充电)和一个guauged $l_μ-l_μ-l_-l_-l_-l_-l_ thememetry。将新夸克与SM的混合在Electroweak对称性破坏之后,不仅可以解释$ z \ b \ bar b $数据,而且还产生了对$ b \ $ b \ of $ b \ for s \ ell^+el^+ell^ell^ell^ - $ $ transitions的过渡。连同Lepton风味普遍性违反了涉及带电标量和重型夸克的循环诱导的$ Z^\ Prime $企鹅产生的效果,它非常适合数据($ 6.1 \,σ$比SM更好)。此外,带电的标量(中性矢量)给出了$μ\ toeνν$($τ\ toμνν$)的必要建设性树水平(环)效应,该效应自然可以解释Caa($ {\ rm br} br} [τ\toμνν]/{\ rm br} [μ\ toeνν] $)。

In this article we propose a simple model which can provide a combined explanation of the $Z\to b\bar b$ forward-backward asymmetry, the Cabibbo Angle Anomaly (CAA), $τ\toμνν$ and $b\to s\ell^+\ell^-$ data. This model is obtained by extending the Standard Model (SM) by two heavy vector-like quarks (an $SU(2)_L$ doublet (singlet) with hypercharge $-5/6$ (-1/3)), two new scalars (a neutral and a singly charged one) and a gauged $L_μ-L_τ$ symmetry. The mixing of the new quarks with the SM ones, after electroweak symmetry breaking, does not only explain $Z\to b\bar b$ data but also generates a lepton flavour universal contribution to $b\to s\ell^+\ell^-$ transitions. Together with the lepton flavour universality violating effect, generated by loop-induced $Z^\prime$ penguins involving the charged scalar and the heavy quarks, it gives an excellent fit to data ($6.1\,σ$ better than the SM). Furthermore, the charged scalar (neutral vector) gives a necessarily constructive tree-level (loop) effect in $μ\to eνν$ ($τ\to μνν$), which can naturally account for the CAA (${\rm Br}[τ\toμνν]/{\rm Br}[τ\to eνν]$ and ${\rm Br}[τ\toμνν]/{\rm Br}[μ\to eνν]$).

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