论文标题
三角形晶格上的Spin-1/2 Heisenberg Antiferromagnet的磁化
Magnetization of the spin-1/2 Heisenberg antiferromagnet on the triangular lattice
论文作者
论文摘要
经过数十年的辩论，现在有一个粗略的共识，在零温度下，三角晶格上的旋转$ 1/2 $ heisenberg antiferromagnet是三个公共的$ 120^\ circ $磁性序列，与最初提议的量子旋转液体相反。但是，在各种方法中报道的磁化中仍然存在很大的差异。为了解决这个问题，在这项工作中，我们通过张量 - 网络状态算法重新审视该模型。每键$ e_b $的地面能量和热力学极限中的每旋转$ m_0 $的磁化是高精度获得的。前者估计为$ e_b = -0.18334（10）$。该值与系列扩展中的相符非常吻合。牢固地确认了三个公共磁性顺序，并确定磁化化为$ m_0 = 0.161（5）$。它的经典价值约为$ 32 \％$，略低于系列扩展的下限。与Monte Carlo和密度 - 矩阵重质化组的最佳估计值相比，我们的结果约为$ 20 \％$ $。该磁性顺序与三体相关性的进一步分析是一致的。因此，我们的工作为该原型模型提供了新的基准结果。
After decades of debate, now there is a rough consensus that at zero temperature the spin-$1/2$ Heisenberg antiferromagnet on the triangular lattice is three-sublattice $120^\circ$ magnetically ordered, in contrast to a quantum spin liquid as originally proposed. However, there remains considerable discrepancy in the magnetization reported among various methods. To resolve this issue, in this work we revisit this model by the tensor-network state algorithm. The ground-state energy per bond $E_b$ and magnetization per spin $M_0$ in the thermodynamic limit are obtained with high precision. The former is estimated to be $E_b = -0.18334(10)$. This value agrees well with that from the series expansion. The three-sublattice magnetic order is firmly confirmed and the magnetization is determined as $M_0 = 0.161(5)$. It is about $32\%$ of its classical value and slightly below the lower bound from the series expansion. In comparison with the best estimated value by Monte Carlo and density-matrix renormalization group, our result is about $20\%$ smaller. This magnetic order is consistent with further analysis of the three-body correlation. Our work thus provides new benchmark results for this prototypical model.
